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Molarity and Dilution: How to Calculate Solution Concentration

Learn how to calculate molarity, prepare solutions, and perform dilution calculations with step-by-step examples and the M₁V₁ = M₂V₂ formula.

Samanyu Sathyamoorthi · General Chemistry · September 29, 2026
Molarity and Dilution: How to Calculate Solution Concentration

Solutions are everywhere in chemistry, from the hydrochloric acid in your stomach to the saline drip in a hospital IV bag. Understanding how to describe, calculate, and manipulate the concentration of solutions is one of the most practical skills you will learn in chemistry. In this guide, we will cover what solutions are, how molarity works as a concentration unit, how to perform molarity calculations, how to prepare solutions in the lab, and how to use the dilution equation to adjust concentrations. By the end, you will be confident solving the most common solution concentration problems you will encounter in high school and introductory college chemistry.

What is a solution?

A solution is a homogeneous mixture of two or more substances. In a solution, the components are evenly distributed at the molecular level, meaning you cannot see the individual substances or separate them by filtration. The most familiar example is salt water: when you dissolve table salt (sodium chloride) in water, the sodium and chloride ions disperse uniformly throughout the liquid. The result looks like a single substance, but it is actually a mixture.

Solutions can exist in any phase. A solid solution example is bronze, an alloy of copper and tin. A gaseous solution example is air, a mixture of nitrogen, oxygen, and other gases. However, in chemistry courses, the term solution most often refers to a liquid solution in which a solid, liquid, or gas is dissolved in a liquid.

Solute, solvent, and concentration

In any solution, the substance being dissolved is called the solute, and the substance doing the dissolving is called the solvent. The solvent is usually the component present in the greater amount. In salt water, salt is the solute and water is the solvent. Concentration is a measure of how much solute is dissolved in a given amount of solution or solvent. A concentrated solution has a large amount of solute relative to solvent, while a dilute solution has a small amount of solute relative to solvent.

There are many ways to express concentration, but the most commonly used unit in chemistry is molarity. Other units include molality, mass percent, volume percent, and parts per million. Each has its advantages depending on the context, but molarity is the standard for most laboratory and classroom work.

What is molarity?

Molarity (M) is defined as the number of moles of solute per liter of solution. The formula is M = n/V, where n is the number of moles of solute and V is the volume of the solution in liters. A 1.00 M solution of sodium chloride contains 1.00 mole of NaCl dissolved in enough water to make exactly 1.00 liter of solution. Note that the volume refers to the total volume of the solution, not the volume of the solvent alone.

Molarity is useful because it directly relates the amount of solute (in moles) to the volume of solution, making it easy to calculate how much solute is present in any given volume. If you have 500 mL of a 0.200 M solution, you can quickly calculate that it contains 0.200 × 0.500 = 0.100 moles of solute.

How to calculate molarity: worked examples

Example 1: You dissolve 5.85 grams of sodium chloride (NaCl) in enough water to make 250.0 mL of solution. What is the molarity? First, convert grams to moles. The molar mass of NaCl is 22.99 + 35.45 = 58.44 g/mol. Moles of NaCl = 5.85 g ÷ 58.44 g/mol = 0.1001 mol. Next, convert the volume to liters: 250.0 mL = 0.2500 L. Finally, calculate molarity: M = 0.1001 mol ÷ 0.2500 L = 0.400 M.

Example 2: What mass of potassium hydroxide (KOH) is needed to prepare 2.00 L of a 0.500 M solution? Start with the molarity formula rearranged to solve for moles: n = M × V = 0.500 × 2.00 = 1.00 mol. The molar mass of KOH is 39.10 + 16.00 + 1.008 = 56.11 g/mol. Mass = 1.00 mol × 56.11 g/mol = 56.1 g. You would need to dissolve 56.1 grams of KOH in enough water to make 2.00 liters of solution.

How to prepare a solution of known molarity

Preparing a solution in the lab requires careful technique. First, calculate the mass of solute needed using the molarity formula as shown above. Weigh the solute on an analytical balance. Transfer the solute to a volumetric flask of the appropriate size. A volumetric flask is a specialized piece of glassware with a narrow neck and a calibration mark that indicates a precise volume. Add distilled water to the flask, swirling to dissolve the solute completely. Once the solute is fully dissolved, add water carefully until the bottom of the meniscus sits exactly on the calibration mark. Stopper the flask and invert it several times to ensure thorough mixing.

It is important to add water to the solute, not the other way around, especially when working with strong acids or bases that release heat upon dissolving. Always use distilled or deionized water to avoid introducing impurities. And remember: the volume in the molarity formula is the final volume of the solution, not the volume of water added. This is why you dissolve the solute first and then add water to the mark.

Dilution: the concept

Dilution is the process of reducing the concentration of a solution by adding more solvent. When you add water to a concentrated solution, the amount of solute stays the same, but it is now spread out in a larger volume, so the concentration decreases. Dilution is one of the most common procedures in chemistry labs because stock solutions are often prepared at high concentrations and then diluted to the working concentration needed for a particular experiment.

The key principle behind dilution is that the number of moles of solute does not change. Before dilution, the moles of solute equal M₁ × V₁ (the initial molarity times the initial volume). After dilution, the moles of solute equal M₂ × V₂ (the final molarity times the final volume). Since the moles are the same before and after, we get the dilution equation.

The dilution equation: M₁V₁ = M₂V₂

The dilution equation is M₁V₁ = M₂V₂, where M₁ is the initial molarity, V₁ is the initial volume, M₂ is the final molarity, and V₂ is the final volume. This equation can be used to solve for any one of the four variables when the other three are known. The volumes can be in any unit (mL, L, etc.) as long as both V₁ and V₂ are in the same unit.

Worked example 1: You have 100.0 mL of a 6.00 M HCl solution. You want to dilute it to 1.00 M. What final volume do you need? Using M₁V₁ = M₂V₂: (6.00)(100.0) = (1.00)(V₂). V₂ = 600.0 mL. You would add enough water to bring the total volume to 600.0 mL. That means adding 500.0 mL of water to the original 100.0 mL.

Worked example 2: You need 250.0 mL of a 0.100 M NaOH solution, and your stock solution is 2.00 M. What volume of stock solution should you use? Using M₁V₁ = M₂V₂: (2.00)(V₁) = (0.100)(250.0). V₁ = 25.0/2.00 = 12.5 mL. You would measure 12.5 mL of the 2.00 M stock solution and add water to bring the total volume to 250.0 mL.

Other concentration units

While molarity is the most common concentration unit in general chemistry, other units are used in specific contexts. Molality (m) is the number of moles of solute per kilogram of solvent (not solution). Unlike molarity, molality does not change with temperature because mass does not expand or contract the way volume does. Molality is used in colligative property calculations such as boiling point elevation and freezing point depression.

Mass percent (or weight percent) is the mass of solute divided by the total mass of the solution, multiplied by 100. For example, a 5% NaCl solution contains 5 grams of NaCl per 100 grams of solution. Volume percent is similar but uses volumes: a 70% isopropyl alcohol solution contains 70 mL of isopropyl alcohol per 100 mL of solution. Parts per million (ppm) is used for very dilute solutions and equals milligrams of solute per liter of solution (for aqueous solutions where the density is approximately 1 g/mL). Water quality standards, for example, often specify contaminant limits in ppm.

Why concentration matters in chemistry

Concentration is not just a number to calculate for homework problems. It has real consequences in the lab and in the world. In chemical reactions, the rate of reaction depends on the concentration of the reactants: higher concentrations generally lead to faster reactions because molecules collide more frequently. In medicine, drug dosages are calculated based on concentration to ensure patients receive the correct amount of active ingredient. In environmental science, pollutant concentrations determine whether water is safe to drink or air is safe to breathe. In cooking, the concentration of salt or sugar in a brine or syrup determines the flavor and preservation properties of the food.

Understanding concentration also helps you work safely in the lab. A 1 M solution of hydrochloric acid is mildly corrosive, but a 12 M solution is extremely dangerous and must be handled with great care. Knowing the concentration of the solutions you are working with allows you to assess risks and take appropriate precautions.

Using MyChemLab AI's molar mass calculator for solution prep

Calculating molarity requires knowing the molar mass of your solute, and this is where MyChemLab AI's molar mass calculator becomes invaluable. Simply enter the chemical formula of your solute, and the calculator instantly provides the molar mass with the correct number of significant figures. From there, you can use the AI tutor to walk through molarity calculations step by step, checking your work at each stage. The tutor can also help you practice dilution problems, converting between concentration units, and understanding when to use molarity versus molality. Whether you are preparing for a lab practical or studying for an exam, MyChemLab AI gives you the tools and guidance to master solution concentration calculations with confidence.